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Svoyaya
@Svoyaya
August 2022
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Сумма шести первых членов арифметической прогрессии (An) равна 9, A3-A2=0,4 . Найдите первый член прогрессии A1 .
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Dимасuk
Verified answer
D = a₃ - a₂ = 0,4
S₆ = 6·(2a₁ + 5d)/2 = 3(2a₁ + 5d) = 6a₁ + 15d
6a₁ + 15d = 9
2a₁ + 5d = 3
Подставляем d = 0,4:
2a₁ + 2 = 3
2a₁ = 3 - 2
2a₁ = 1
a₁ = 0,5
Ответ: a
₁
= 0,5.
1 votes
Thanks 2
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Answers & Comments
Verified answer
D = a₃ - a₂ = 0,4S₆ = 6·(2a₁ + 5d)/2 = 3(2a₁ + 5d) = 6a₁ + 15d
6a₁ + 15d = 9
2a₁ + 5d = 3
Подставляем d = 0,4:
2a₁ + 2 = 3
2a₁ = 3 - 2
2a₁ = 1
a₁ = 0,5
Ответ: a₁= 0,5.