[tex] x^{2} *0,3^x-0,3^x^-^2\ \textless \ 0[/tex] решите неравенство пожалуйстаааа. Created by elya97elya97. algebra-ru

метод интервалов:2. + - +-----------(-10/3)--------(10/3)----------------->x4. x∈(-10/3;10/3)

tex] решите неравенство пожалуйстаааа...

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[tex] x^{2} *0,3^x-0,3^x^-^2\ \textless \ 0[/tex] решите неравенство пожалуйстаааа

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kirichekov

Verified answer

$x^{2} * 0,3^{x} - 0,3^{x-2} \ \textless \ 0

 x^{2} * 0,3^{x} - 0,3^{x} *( \frac{3}{10} ) ^{-2} \ \textless \ 0

 0,3^{x} *( x^{2} - (\frac{10}{3} )^{2} )\ \textless \ 0$
$0,3^{x} \ \textgreater \ 0, =\ \textgreater \ x^{2} -( \frac{10}{3} ) ^{2} \ \textless \ 0$
метод интервалов:
$1. 

 x^{2} -( \frac{10}{3}) ^{2} =0

 x_{1} =- \frac{10}{3} 

 x_{2} = \frac{10}{x}$
2. + - +
-----------(-10/3)--------(10/3)----------------->x
4. x∈(-10/3;10/3)

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