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elya97elya97
@elya97elya97
August 2022
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[tex] \frac{3}{ \sqrt{27^x} } \ \textless \ \frac{3}{9^x} [/tex] решите пожалуйсто срооочно
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kirichekov
Verified answer
основание степени а=3, 3>1. знак неравенства не меняем.
1-1,5x<1-2x
0,5x<0
x<0
x∈(-∞;0)
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Answers & Comments
Verified answer
основание степени а=3, 3>1. знак неравенства не меняем.
1-1,5x<1-2x
0,5x<0
x<0
x∈(-∞;0)