помогите пожалуйставычислить[tex] \sqrt{2} \cos( \frac{\pi}{12} ) + \sqrt{6} \sin( \frac{\pi}{12} ) [/tex]. Created by dovnara620. algebra-ru

Ответ:2Объяснение:

tex]...

dovnara620 @dovnara620

July 2022 1 9 Report

помогите пожалуйста
вычислить

[tex] \sqrt{2} \cos( \frac{\pi}{12} ) + \sqrt{6} \sin( \frac{\pi}{12} ) [/tex]

Answers & Comments

guvanch021272

Ответ:

Объяснение:

$\sqrt{2}cos\frac{\pi}{12}+\sqrt{6}sin\frac{\pi}{12}=2\sqrt{2}(\frac{1}{2} cos\frac{\pi}{12}+\frac{\sqrt{3}}{2} sin\frac{\pi}{12})=2\sqrt{2}(sin\frac{\pi }{6}cos\frac{\pi}{12}+cos\frac{\pi }{6}sin\frac{\pi}{12})=2\sqrt{2}sin(\frac{\pi }{6}+\frac{\pi}{12})=2\sqrt{2}sin\frac{\pi }{4}=2\sqrt{2}*\frac{\sqrt{2} }{2}=2$

1 votes Thanks 0

Answers & Comments

c1607ceddf91e99891d1b56fbf5660f9

c828aaa5c9d46bbc801d1dab6e0e0104

fa1ebe1385515c236c0f5dd4e09296ec

2d29e6a03d1fc42090136f888b9acd12

pomogite reshit pozhalujsta4197f710a4e961a274c283914e516750 76883

v trapecii dliny osnovanij ravny 10 i 20 a bokovyh storon 6 i 8najdite ploshad

pomogite reshit pozhalujstad670236abb34bf12f7bd763ddd871e81 3783

texi najdite najbolshij otricatelnyj koren

tex4171b6215bea9a4a27520fd398876a1a 39393

pomogite reshitsin6arcctg 34arctg5

рекомендуемые вопросы

Helpful Links

Helpful Social