Решите квадратное уравнение с корнем : [tex]\sqrt{2} x^2-x(\sqrt{2} +3)+1=0[/tex]. Created by vityamath. algebra-ru

Ответ:Объяснение:

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vityamath @vityamath

August 2022 1 79 Report

Решите квадратное уравнение с корнем : [tex]\sqrt{2} x^2-x(\sqrt{2} +3)+1=0[/tex]

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stanmat

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Ответ:

$x = \frac{{\sqrt 2 + 3 \pm \sqrt {2\sqrt 2 + 11} }}{{2\sqrt 2 }}$

Объяснение:

$\begin{array}{l}\sqrt 2 {x^2} - x(\sqrt 2 + 3) + 1 = 0\\D = {(\sqrt 2 + 3)^2} - 4\sqrt 2 = 2 + 6\sqrt 2 + 9 - 4\sqrt 2 = 2\sqrt 2 + 11\\x = \frac{{\sqrt 2 + 3 \pm \sqrt {2\sqrt 2 + 11} }}{{2\sqrt 2 }}\end{array}$

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vityamath August 2022 | 0 Ответы

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