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drwnd
@drwnd
July 2022
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решите пожалуйста [tex] \int\ \frac{sin2x}{ \sqrt{4+sin^2x} } \, dx [/tex]
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Alexаndr
Verified answer
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sedinalana
T=√(4+sin²x)⇒t²=4+sin²x
2tdt=2√(4+sin²x)*2*2sinxcosx/2√(4+sin²x)=sin2xdx⇒dx=2tdt/sin2x
∫sin2xdx/√(4+sin²x)=∫sin2x*2tdt/sin2x*t=∫2dt=2t+C=2√(4+sin²x)+C
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2tdt=2√(4+sin²x)*2*2sinxcosx/2√(4+sin²x)=sin2xdx⇒dx=2tdt/sin2x
∫sin2xdx/√(4+sin²x)=∫sin2x*2tdt/sin2x*t=∫2dt=2t+C=2√(4+sin²x)+C