Ответ:
1) f'(x) = 4x^3 - 6x^2 + 1
f'(-1) = 4(-1)^3 - 6(-1)^2 + 1
= -4 - 6 + 1
= -9
2) f'(x) = x^2 - x - 2
f'(3) = (3)^2 - (3) - 2
= 9 - 3 - 2
= 4
3) f'(x) = 1/(2√x) - 32x
f'(1/4) = 1/(2√(1/4)) - 32(1/4)
= 1/(2(1/2)) - 8
= 1 - 8
= -7
4) f'(x) = (2(1-x) - (-3x))/((x-1)^2)
f'(2) = (2(1-2) - (-3(2)))/((2-1)^2)
= (2(-1) + 6)/(1^2)
= (-2 + 6)/1
= 4/1
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Ответ:
1) f'(x) = 4x^3 - 6x^2 + 1
f'(-1) = 4(-1)^3 - 6(-1)^2 + 1
= -4 - 6 + 1
= -9
2) f'(x) = x^2 - x - 2
f'(3) = (3)^2 - (3) - 2
= 9 - 3 - 2
= 4
3) f'(x) = 1/(2√x) - 32x
f'(1/4) = 1/(2√(1/4)) - 32(1/4)
= 1/(2(1/2)) - 8
= 1 - 8
= -7
4) f'(x) = (2(1-x) - (-3x))/((x-1)^2)
f'(2) = (2(1-2) - (-3(2)))/((2-1)^2)
= (2(-1) + 6)/(1^2)
= (-2 + 6)/1
= 4/1
= 4