A4. (sin (x-Π/6) - tg Π/4)*(cos (x+Π/6) + tg Π/3) = 0
Если произведение равно 0, то хотя бы один множитель равен 0.
1) sin (x-Π/6) - tg Π/4 = 0
sin (x-Π/6) = tg Π/4 = 1
x - Π/6 = Π/2 + 2Πk
x = Π/2 + Π/6 + 2Πk = 4Π/6 + 2Πk = 2Π/3 + 2Πk, k € Z
Наименьший положительный корень: 2Π/3.
2) cos (x+Π/6) + tg Π/3 = 0
cos (x+Π/6) = - tg Π/3 = -√3 < -1
Корней нет.
Ответ: 2Π/3.
A5. (cos (x+Π/3) + ctg Π/4)*(sin (x-Π/3) + ctg Π/6) = 0
1) cos (x+Π/3) + ctg Π/4 = 0
cos (x+Π/3) = -ctg Π/4 = -1
x + Π/3 = Π + 2Πk
x = Π - Π/3 + 2Πk = 2Π/3 + 2Πk, k € Z
2) sin (x-Π/3) + ctg Π/6 = 0
sin (x-Π/3) = - ctg Π/6 = -√3 < -1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
A4. (sin (x-Π/6) - tg Π/4)*(cos (x+Π/6) + tg Π/3) = 0
Если произведение равно 0, то хотя бы один множитель равен 0.
1) sin (x-Π/6) - tg Π/4 = 0
sin (x-Π/6) = tg Π/4 = 1
x - Π/6 = Π/2 + 2Πk
x = Π/2 + Π/6 + 2Πk = 4Π/6 + 2Πk = 2Π/3 + 2Πk, k € Z
Наименьший положительный корень: 2Π/3.
2) cos (x+Π/6) + tg Π/3 = 0
cos (x+Π/6) = - tg Π/3 = -√3 < -1
Корней нет.
Ответ: 2Π/3.
A5. (cos (x+Π/3) + ctg Π/4)*(sin (x-Π/3) + ctg Π/6) = 0
1) cos (x+Π/3) + ctg Π/4 = 0
cos (x+Π/3) = -ctg Π/4 = -1
x + Π/3 = Π + 2Πk
x = Π - Π/3 + 2Πk = 2Π/3 + 2Πk, k € Z
Наименьший положительный корень: 2Π/3.
2) sin (x-Π/3) + ctg Π/6 = 0
sin (x-Π/3) = - ctg Π/6 = -√3 < -1
Корней нет.
Ответ: 2Π/3.