Ответ:
Пошаговое объяснение:
15 . ( х > 0 ) : x = ( x^(1/2))² ; x⁸ = ( x⁴ )² ; x^(1/4 ) = ( x^(1/8) )² ; x^(- 1/3 ) = ( x^(- 1/6) )².
16 . ( a > 0) : a = ( a^(1/3 ))³ ; a⁶ = ( a² )³ ; a^(1/4) = ( a^(1/12) )³; a^(- 1/3 ) = ( a^(- 1/9) )³ ;
√a = ⁶√( √a ) ³ .
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Пошаговое объяснение:
15 . ( х > 0 ) : x = ( x^(1/2))² ; x⁸ = ( x⁴ )² ; x^(1/4 ) = ( x^(1/8) )² ; x^(- 1/3 ) = ( x^(- 1/6) )².
16 . ( a > 0) : a = ( a^(1/3 ))³ ; a⁶ = ( a² )³ ; a^(1/4) = ( a^(1/12) )³; a^(- 1/3 ) = ( a^(- 1/9) )³ ;
√a = ⁶√( √a ) ³ .