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12assua12
@12assua12
August 2022
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Помощь за один пример 35б
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Nina1952
16^х - 19*4^х +48 =0
4^2х - 19*4^х+48=0
Замена : 4^х=у
У^2 - 19у +48=0
Д= 13
У1= (19+13)/2
У1=16
У2=(19-13)/2
У2=3
4^х=у1
4^х=16
4^х=4^2
Х1=2
4^х=у2
4^х=3
Х2= log4 3
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Answers & Comments
4^2х - 19*4^х+48=0
Замена : 4^х=у
У^2 - 19у +48=0
Д= 13
У1= (19+13)/2
У1=16
У2=(19-13)/2
У2=3
4^х=у1
4^х=16
4^х=4^2
Х1=2
4^х=у2
4^х=3
Х2= log4 3