Ответ: №1 .
[tex]\displaystyle \int \frac{x\, dx}{Ax^2+Bx+C}\ \ ,\ \ \ A\ne 0\ ,\ B\ne 0\ ,\ C\ne 0\\\\\\d(Ax^2+Bx+C)=(2Ax+B)\, dx\ \ \Rightarrow \ \ x\, dx=\Big(\frac{1}{2A}\cdot (2Ax+B)-\frac{B}{2A}\Big)\, dx[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ: №1 .
[tex]\displaystyle \int \frac{x\, dx}{Ax^2+Bx+C}\ \ ,\ \ \ A\ne 0\ ,\ B\ne 0\ ,\ C\ne 0\\\\\\d(Ax^2+Bx+C)=(2Ax+B)\, dx\ \ \Rightarrow \ \ x\, dx=\Big(\frac{1}{2A}\cdot (2Ax+B)-\frac{B}{2A}\Big)\, dx[/tex]