Ответ:
[tex]\left\{\begin{array}{l}2x-3y+z=-3\\3x+2y+3z=5\\-x+2y+2z=7\end{array}\right\\\\\\\left(\begin{array}{cccc}2&-3&1&|-3\\3&2&3&|\ 5\\-1&2&2&|\ 7\end{array}\right)\sim \ 1str.\longleftrightarrow 3str.\ \left(\begin{array}{cccc}-1&2&2&|7\\3&2&3&|\ 5\\2&-3&1&\ |-3\end{array}\right)\sim[/tex]
1 cтрочку*3+ 2стр. ; 1стр.*2+ 3стр.
[tex]\sim \left(\begin{array}{cccc}-1&2&2&|\ 7\\0&8&9&\ |\ 26\\0&1&5&\ |\ 11\end{array}\right)\sim \ 2str.\longleftrightarrow 3str.\ \left(\begin{array}{cccc}-1&2&2&|\ 7\\0&1&5&\ |\ 11\\0&8&9&|\ 26\end{array}\right)\sim[/tex]
2 строчку*(-8) + 2 стр.
[tex]\sim \left(\begin{array}{cccl}-1&2&2&|\ 7\\0&1&5&|\ 11\\0&0&-31&|-62\end{array}\right)\\\\\\\left\{\begin{array}{cccl}-x+2y+2z=7\\\qquad\ \ y+5z=11\\\qquad \ \ -31z=-62\end{array}\right\ \ \left\{\begin{array}{cccl}-x+2y+4=7\\\qquad\ \ y+10=11\\\qquad \ \ z=2\end{array}\right\ \ \left\{\begin{array}{cccl}-x+2=3\\y=1\\z=2\end{array}\right\ \ \left\{\begin{array}{cccl}x=-1\\y=1\\z=2\end{array}\right[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
[tex]\left\{\begin{array}{l}2x-3y+z=-3\\3x+2y+3z=5\\-x+2y+2z=7\end{array}\right\\\\\\\left(\begin{array}{cccc}2&-3&1&|-3\\3&2&3&|\ 5\\-1&2&2&|\ 7\end{array}\right)\sim \ 1str.\longleftrightarrow 3str.\ \left(\begin{array}{cccc}-1&2&2&|7\\3&2&3&|\ 5\\2&-3&1&\ |-3\end{array}\right)\sim[/tex]
1 cтрочку*3+ 2стр. ; 1стр.*2+ 3стр.
[tex]\sim \left(\begin{array}{cccc}-1&2&2&|\ 7\\0&8&9&\ |\ 26\\0&1&5&\ |\ 11\end{array}\right)\sim \ 2str.\longleftrightarrow 3str.\ \left(\begin{array}{cccc}-1&2&2&|\ 7\\0&1&5&\ |\ 11\\0&8&9&|\ 26\end{array}\right)\sim[/tex]
2 строчку*(-8) + 2 стр.
[tex]\sim \left(\begin{array}{cccl}-1&2&2&|\ 7\\0&1&5&|\ 11\\0&0&-31&|-62\end{array}\right)\\\\\\\left\{\begin{array}{cccl}-x+2y+2z=7\\\qquad\ \ y+5z=11\\\qquad \ \ -31z=-62\end{array}\right\ \ \left\{\begin{array}{cccl}-x+2y+4=7\\\qquad\ \ y+10=11\\\qquad \ \ z=2\end{array}\right\ \ \left\{\begin{array}{cccl}-x+2=3\\y=1\\z=2\end{array}\right\ \ \left\{\begin{array}{cccl}x=-1\\y=1\\z=2\end{array}\right[/tex]